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PSTCL Full Form, PSTCL Recruitment 2025 – 270 Vacancies, Eligibility, Salary & Online Form

Last updated on March 5th, 2026 at 04:25 pm

If you are searching for “PSTCL full form” or looking for the latest PSTCL Recruitment 2025, this article provides complete information including full form, vacancies, qualifications, fees, online form link, and selection process. The Punjab State Transmission Corporation Limited (PSTCL) has released Advt. No. 12/2025 for 270 various posts. The online application starts from 17 November 2025.



PSTCL Full Form, PSTCL Recruitment 2025 – 270 Vacancies, Eligibility, Salary & Online Form

 

Table Of Contents

PSTCL Full Form

PSTCL Full Form = Punjab State Transmission Corporation Limited

It is a government organization responsible for electricity transmission across Punjab.


PSTCL Recruitment 2025 – Overview

DetailsInformation
Recruitment BodyPunjab State Transmission Corporation Limited (PSTCL)
Form ModeOnline Form
Job LocationPunjab
Monthly PayAs per Advertisement
Job BasisPermanent
Advertisement No.12/2025
Total Vacancies270 Posts

Important Dates

EventDate
Notification Out17/11/2025
Starting Date17/11/2025
Last Date16/12/2025 (11:55 PM)
Exam DateJanuary 2026 (Tentative)

Application Fees

CategoryFees
General / OBC / EWS₹1416/-
SC Candidates₹885/-
PH (Divyang)₹885/-
Payment ModeOnline

Age Limit (as on 01/01/2025)

  • 18–37 Years
  • Age relaxation as per Punjab Govt. rules.

PSTCL Recruitment 2025 – Post-wise Qualification

Post NameQualification
Assistant Engineer (OT) ElectricalBE/B.Tech/B.Sc Engineering in Electrical/Electrical & Electronics with 55% marks
Assistant Manager (IT)BE/B.Tech/B.Sc CS/IT with 55% OR MCA/PG in IT
Accounts OfficerCA / CWA / CMA
Divisional AccountantB.Com with 60% OR CA/CWA/CMA
Junior Engineer (Electrical)Diploma (60%) OR BE/B.Tech/B.Sc Engineering (50%) in Electrical
Junior Engineer (Civil)Diploma (60%) OR BE/B.Tech/B.Sc Engineering (50%) in Civil
Junior Engineer (Communication)Diploma (60%) OR BE/B.Tech/B.Sc Engineering (50%) in Electronics/Telecommunication
Law Officer Grade-IILLB with 60% + 3 Years Experience
Telephone Mechanic10th + ITI (Radio/Wireless Mechanic) OR Diploma in ECE (50%)
Lower Division Clerk / TypistAny Bachelor’s Degree + 120 Hours OR ‘O’ Level Computer Course
Lower Division Clerk (Accounts)B.Com with 60% + 120 Hours OR ‘O’ Level Computer Course

Note: Punjabi subject in Class 10th is mandatory for all posts.


PSTCL Vacancy 2025 – Total 270 Posts

Post NameVacancyPost NameVacancy
AE (OT) Electrical – PSTCL21AE (OT) Electrical – PSPCL40
Assistant Manager (IT)03Accounts Officer02
Divisional Accountant11Junior Engineer (Electrical)110
Junior Engineer (Civil)15Law Officer Grade-II02
Junior Engineer (Communication)06LDC / Typist35
Telephone Mechanic10LDC (Accounts)15

Selection Process

  1. CBT Written Exam
  2. Document Verification
  3. Medical Examination

How to Apply for PSTCL Recruitment 2025

  1. Visit the official website.
  2. Click on “Apply Online – Advt. 12/2025”.
  3. Register with email and mobile number.
  4. Fill the application form.
  5. Upload required documents.
  6. Pay the application fee.
  7. Submit the form and take a printout.

TypeIssued OnLink
PSPCL Assistant Engineer Result05/03/2026Click Here
DV Schedule27/02/2026Click Here
Get Exam Result25/02/2026Click Here
Answer Key / Objection20/01/2026Click Here
Answer Key Notice20/01/2026Click Here
Admit Card10/01/2026Click Here
Fill Online Form17/11/2025Click Here
Full Notification17/11/2025Click Here
Official Website17/11/2025Click Here


Top 5 FAQs – PSTCL Full Form & Recruitment

Q1. What is the full form of PSTCL?

PSTCL full form is Punjab State Transmission Corporation Limited.

Q2. How many vacancies are released in PSTCL Recruitment 2025?

A total of 270 vacancies are released.

Q3. What is the last date to apply for PSTCL 2025?

The last date is 16 December 2025 (11:55 PM).

Q4. What is the exam date for PSTCL Recruitment 2025?

The CBT exam is expected in January 2026.

Q5. What is the application fee for General category?

General/OBC/EWS candidates must pay ₹1416/-.


 

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